4. For a particular large group of people, blood types are distributed as shown
ID: 3064372 • Letter: 4
Question
4. For a particular large group of people, blood types are distributed as shown below. (Note that each person is classified as having exactly one of these blood types.)
(a) Maria has type B blood. She can safely receive blood transfusions from people with blood types O and B. What is the probability that a randomly selected person will be able to donate blood to Maria?
A. 0.36
B. 0.18
C. 0.01
D. None of the above.
(b) If two people are selected at random, what is the probability that both people selected will have type O blood?
A. 0.34
B. 0.0289
C. 0.17
D. None of the above.
(c) The probability that a randomly selected person will have type AB blood is
A. 0.01
B. 0.17
C. 0.47
D. None of the above.
7. Suppose that, for students who are enrolled in college algebra, 79 percent are freshmen, 45 percent are female, and 31 percent are female and are freshmen. Your answers below should be entered as decimals and rounded to three decimal places.
(a) One student will be selected at random. What is the probability that the selected student will be a freshman or female (or both)?
(b) One student will be selected at random. What is the probability that the selected student will not be a freshman?
(c) Two students will be independently selected at random. What is the probability that both of the selected students will be female?
Blood Type O A B AB Probability 0.17 0.35 0.01 ?Explanation / Answer
4)
a)
Probability that selected person can donate blood to maria =
P(B blood) + P( O blood)
= 0.17 + 0.01
= 0.18
b)
P(Both type O blood) = P( First type O blood) * P(Second type O blood)
= 0.17 * 0.17
= 0.0289
c)
Sum of probabilities must be equal to 1.
P(O Blood) + P(A Blood) + P(B Bllod) + P( AB Blood) =
0.17 + 0.35 + 0.01 + P(AB Blood) = 1
P( AB Blood) = 0.47
7)
P(Freshman) = 0.79, P(Female) = 0.45 , P( Female AND freshman) = 0.31
a)
P( Female OR freshman) = P(Freshman)+P(Female) - P( Female AND freshman)
= 0.79 + 0.45 - 0.31
= 0.93
b)
P( Not freshman) = P( Female) - P( Female AND freshman)
= 0.45 - 0.31
= 0.14
c)
P(Both female) = P(first female) * P(Second female)
= 0.45 + 0.45
= 0.2025
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