4, -12 points JKEStat11 5..055. x is a binomial random variable. (Give your answ

Question

4, -12 points JKEStat11 5..055. x is a binomial random variable. (Give your answers correct to three decimal places.) + My n-3, x-2, p-0.7 (a) Calculate the probability of x for: P(x)- n-8, x-8, p0.25 (b) Calculate the probability of x for: P(x) - n-4, x-0, p-0.5 (c) Calculate the probability of x for: P(x) - (d) Calculate the probability of x for: n-9, x-4, p 0.45 P(x) - n-7, p-0.4 (e) Calculate the probability of x for: P(x) x-1, n-3, x-3, p-0.8 (f) Calculate the probability of x for: P(x) - Need Help? ReadItTaik to a Tuter -12 points JKEStat11 5..065. The survival rate during a risky operation for patients with no other hope of survival is 70%. what is the probability that exactly four of the next five patients survive this operation? (Give your answer correct to three decimal places.) + My Need Help? inanul Lemonte

Explanation / Answer

a) n = 3 , x = 2 , p =0.7

P[x=2]= C(3,2)*(0.7)^2*(1-0.7)^1

= 0.441

b)

n = 8 , x = 8, p =0.25

P[x=8]= C(8,8)*(0.25)^8*(1-0.25)^0

= 0.000

c)

n = 4 , x = 0, p =0.5

P[x=0]= C(4,0)*(0.5)^0*(1-0.5)^4

= 0.063

d)

n = 9, x = 4, p =0.45

P[x=4]= C(9,4)*(0.45)^4*(1-0.45)^5

= 0.260

e)

n=7 , x= 1 , p = 0.4

P[x=1] = C(7,1)*(0.4)^1*(1-0.4)^6

= 0.131

f)  

n= 3 , x= 3 , p = 0.8

P[x=3] = C(3,3)*(0.8)^3*(1-0.8)^0

= 0.512

Question ) p = 0.70, n = 5 , x = 4

P[x=4] = C(5,4)*(0.70)^4*(1-0.70)^1

= 0.360

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