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4)) 16% D Mon 5:10 PM a Chrome File Edit View History Bookmarks People Window Help A Home-Myusu fi Dwww.webassign.net/web/Student/Assignment-Responses/submit2dep=1 1594592 :. Apps Bookmarks A usu canvas chem sapling e chegg B Bodybuilding.com a Songkick-Conce Austin x Ellucian Degree Works - Us x Homework 8 x Chegg Study | Guided Sol xSean White Stats, News, V x A preReq med school slcc canvas S slcc login Other Bookmarks » ew 7. -12 points CJ8 9.P.012.Go My Notes Review Conceptual Example 7 before starting this problem. A uniform plank of length 5.0 m and weight 225 N rests horizontally on two supports, with 1.1 m of the plank hanging over the right support (see the drawing). To what distance x can a person who weighs 442 N walk on the overhanging part of the plank before it just begins to tip? | Select-. Go GO Tutorial Read the eBook Section 9.2 Rigid Objects in Equilibrium Read the eBook Section 9.3 Center of Gravity 8. -12 points CJ8 9.P.015 My Notes Interactive Solution 9.15 offers help in modeling this problem A person exerts a horizontal force of 180 N in the test apparatus shown in the drawing. (h 0.25 m.) Find the horizontal force M that his flexor muscle exerts on his forearm magnitude direction -Select # 26 J.

Explanation / Answer

F1 is weight of plank=225N. F2= weight of the person=442N

CM of plank from either end of the plank is at distance = 5m/2 = 2.5m

Distance of CM from the right plank = r = 2.5m – 1.1m = 1.4m

Applying law of conservation of torque at right support

F1*r-F2*x=0

F1*r=F2*x

x= (F1/F2)*r = (225/442)*1.4 = 0.71m

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