A study monitored several thousand people over decades of cigarette usage and re

Question

A study monitored several thousand people over decades of cigarette usage and recorded the incidence of lung cancer, described below, where X is cigarette usage in packs smoked per day and Y is relative risk of cancer. The relative risk is defined as the incidence of lung cancer in the exposed group divided by the incidence of lung cancer in the unexposed group Cig. packs/ day (X): 0 0.51 1.52 2.5 Relative risk (Y): 1513 19 24 27 48.250, (y,-v)2-540.833 Summary statistics:1.250, y14.833, (x,-Z)2-4.375, Calculate the values 0 and (z,-T) (y,-9) that describe the least-squares regression line relating cigarette usage and relative risk of lung cancer. What is 1.04 [1 pt(s)1 Submit Answer Incorrect. Tries 1/3 Previous Tries What is [1 pt(s)] Submit Answer Tries 0/3 According to the model, by what factor does the risk of lung cancer increase for every additional pack? Round your answer to an integer [1 pt(s)] Submit Answer Tries 0/3 What is the residual for (2.5,27)? [2 pt(s)1 Submit Answer Tries 0/3

Explanation / Answer

solution beta0=y intercept

beta1=slope

b1=SSxy/SSx=(x-xbar)(y-ybar)/(x-xbar)^2

=48.250/4.375

= 11.02857

b1 =11.029

(answers rounded to 3decimals)

b0=y bar-b1(xbar)

=(totaly/n)-b1(totalx/n)

=14.833-11.02857(1.250)

= 1.047287

=1.047

y intercept=1.047

ANSWER:1.047

SOlutionc:

In increases by slope

slope=11.029

accrding to model it increases by 11 times

ANSWER 11

Solutiond:

rEGREESION EQ IS

y=1.047+11.029x

fOR x=2.5

y=1.047+11.029*(2.5)

predicted y= 28.6195

residual=observed-predicted=27-28.6195

=-1.6195

Residual=-1.619

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