A store owner surveyed 25 randomly selected customers and found the ages shown (

Question

A store owner surveyed 25 randomly selected customers and found the ages shown (in years). The mean is 30.48 and the standard deviation is 11.05. The owner wants to know if the mean age of all customers is 26 years old. Use the given information to complete parts a through f 26 38 45 36 14 47 16 23 17 16 30 35 20 34 27 47 30 37 43 15 30 38 43 15 40 The alternative hypothesis is two-sided c) What is the value of the test statistic? The test statistic is 2.03 Round to two decimal places as needed.) d) What is the P-value of the test statistic? P-value (Round to four decimal places as needed.)

Explanation / Answer

Solution :

d) The test statistic is 2.03

Using standard normal table,

P(Z > 2.03) = 1 - P(Z < 2.03)

See z value 2.0 in the column and 0.03 in the row of the standard normal table

the corresponding probabiliy is 0.9788 .

P(Z > 2.03) = 1 - P(Z < 2.03) = 1 - 0.9788 = 0.0212

The alternative hypothesis is two-sided .

P-value = 2 * P(Z > 2.03) = 2 * 0.0212 = 0.0424

P-value = 0.0424

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