Answer Question 3 Please L. (6 Polnts) Comparlson of two data sets A laboratory

Question

Answer Question 3 Please

L. (6 Polnts) Comparlson of two data sets A laboratory in lowa City and a laboratory in Madison tested a sample independently and generated the following results: Concentration 0M) Lablowa CityLab Madison Trial 1 Trial 2 Trial 3 0.6411 0.6398 0.6417 0.6329 0.6392 0.6456 Are the results from the two laboratories statistically different? IL. (6 Points) Comparison of two data sets A laboratory in lowa City and a laboratory in Madison tested a sample independently and generated the following results: Concentration (M) Lab lowa City Lab Madison Trial 1 Trial 2 Trial 3 0.6397 0.6388 0.6289 0.6060 0.6185 0.6201 Are the results from the two laboratories statistically different? IlI. (8 Points) Calculating errors in the final results A Ba(OH)2 solution was standardized with KHP through acid-base titration. Calculate the concentration of Ba(O1H)2 and its associated error based on the following experiment data. value SD mass KHP a 000 MW (g/m101) | 204.2212 | 0.038 Vaon (mL) 38.7o .o5 pe here to search

Explanation / Answer

We find upper and lower limit for moles of KHP considering 3 sigma levels.

Molecular mass of Ba(OH)2 = 171.34 g/mol

2 mol of KHP titrate 1 mol of Ba(OH)2

So, moles of BA(OH)2 is between 0.002698/2 = 0.001349 and 0.002692/2 = 0.001346

Mass of Ba(OH)2 is between 0.001349*171.34 = 0.2311g and 0.001346*171.34 = 0.2306g

Concentration of Ba(OH)2 is between 0.2311g/39.64 = 5.830g/L and  0.2306/39.94 = 5.774g/L

value SD upper value lower value mass KHP(g) 0.5504 0.0002 0.5510 0.5498 MW g/mol 204.2212 0.0038 204.2326 204.2098 V of Ba(OH)2 mL 39.79 0.05 39.94 39.64 Moles of KHP 0.002698 0.002692

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.