14 points QUESTION 3 The number of crimes reported (in millions) and the number
ID: 3056224 • Letter: 1
Question
14 points QUESTION 3 The number of crimes reported (in millions) and the number of arrests reported (in millions) by the U.S. Department of Justice for 14 years Adapted from the National Crime Victimization Survey and Uniform Crime Reports) Crimes,1.60 155 1.44 1.40 1.32 1.23 1.22 Arrests, 7s 0.30 6.73 72 068 064 a 63 Crimes,x 123 12z 118 1.16 1.19 121 120 Arrests y 63 062 0 as9 as 061 os8 a) Find the regression equation that models the number of crimes as a function of the number of arrests is y = b) The correlation coefficient is R c) The linear correlation coefficient is R = d) SST = x + e) SSR = f) SSE = ROUND ALL ANSWERS TO 4 DECIMAL PLACES X.XXXxExplanation / Answer
Question 3
Solution:
Regression model for the prediction of dependent variable number of arrests is summarised as below:
(Regression output by using Excel)
Regression Statistics
Multiple R
0.9806
R Square
0.9615
Adjusted R Square
0.9583
Standard Error
0.0147
Observations
14
ANOVA
df
SS
MS
F
P-value
Regression
1
0.0650
0.0650
299.6730
0.0000
Residual
12
0.0026
0.0002
Total
13
0.0676
Coefficients
Standard Error
t Stat
P-value
Lower 95%
Upper 95%
Intercept
0.0206
0.0370
0.5555
0.5887
-0.0601
0.1012
X
0.4916
0.0284
17.3111
0.0000
0.4297
0.5534
Part a
Required regression equation for the prediction of number of arrests is given as below:
Y = 0.4916*X + 0.0206
Part b
The coefficient of determination or the value of R-square is given as below:
R2 = 0.9615
About 96.15% of the variation in the dependent variable number of crimes is explained by the independent variable number of crimes.
Part c
The linear correlation coefficient is given as R = 0.9806
There is a very strong positive linear relationship exists between given two variables number of crimes and number of arrests.
Part d
SST = 0.0676
Part e
SSR = 0.0650
Part f
SSE = 0.0026
(All values are taken from above ANOVA table for regression model.)
Regression Statistics
Multiple R
0.9806
R Square
0.9615
Adjusted R Square
0.9583
Standard Error
0.0147
Observations
14
ANOVA
df
SS
MS
F
P-value
Regression
1
0.0650
0.0650
299.6730
0.0000
Residual
12
0.0026
0.0002
Total
13
0.0676
Coefficients
Standard Error
t Stat
P-value
Lower 95%
Upper 95%
Intercept
0.0206
0.0370
0.5555
0.5887
-0.0601
0.1012
X
0.4916
0.0284
17.3111
0.0000
0.4297
0.5534
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