Crickets 10.3.14 Consider the following two scatterplots based on data gathered

Question

Crickets 10.3.14 Consider the following two scatterplots based on data gathered in a study of 30 crickets, with temperature measured in degrees Fahrenheit and chirp frequency mea 150 140 130 sured in chirps per minute a. If the goal is to predict temperature based on a cricket's chirps per minute, which is the appropriate scatterplot to examine-the one on the left or the one on the right? 110 100 90 80 70 Explain briefly One of the following is the correct equation of the least squares line for predicting temperature from chirps per minute: A. predicted temperature -35.78 0.25 chirps per B. predicted temperature-131.23 3.81 chirps per C. predicted temperature83.54 0.25 chirps per minute 65 70 75 Temp minut 75 minute b. Which is the correct equation? Circle your answer and c. Use the correct equation to predict the temperature when d. Interpret the value of the slope coefficient, in this context, explain briefly. the cricket is chirping at 100 chirps per minute. E 65 for whichever equation you think is the correct one. 7O 80 90 100 110 120 130 140 150 Chirps/min

Explanation / Answer

10.3.14

Answer to the question is as follows:

1.

a. Since temperature is what we have to predict, you must have it on the y-axis.

Hence, The lower one is the right scatter plot

2. Please note that in the lower scatter plot we will have a positive slope to

the best fit eqn as we have our data points seem to be rising with a positive trend

Hence, C is wrong.

The intercept is going to be positive, as it will intercept the +ive y-axis, hence

B is wrong.

Hence, A is correct

b. The correct eqn is Predicted temperature = 35.78 + .25*chips per minute

For the above reasons already mentoned in part a)

c. Predicted temperature = 35.78 + .25*100 = 60.78

d. It means that for a unit rise in chirps/minute the temperature of rises by .25

units. If there was no chirps/minute then the temperaure sis 35.78 units

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