(2) According to government data, 30% of employed women have never been married,

Question

(2) According to government data, 30% of employed women have never been married, number of 10 randomly chosen employed women who have never been married. let z be the (a) What is the probability that exactly 7 of the ten chosen women have never been married? Give your answer using the binomial formula. (b) What is the probability that fewer than 2 have never been married? (c) What is the probability that at least one of the 10 chosun women have never beun married? (d) Suppose that in a sample of ten chosen women, 9 have nuver been married. Is thie unusual outcome? Explain your answer

Explanation / Answer

(2) n = 10

p = 0.3

q = 1 - p = 0.7

P(x) = nCx px qn-x

(a) P(X = 7) = 10C7 x 0.37 x 0.73

= 0.009

(b) P(X < 2) = P(0) + P(1)

= 0.710 + 10x0.3x0.79

= 0.028 + 0.121

= 0.149

(c) P(at least one never married) = 1 - P(0)

= 1 - 0.710

= 0.972

(d) P(9 have or more never been married) = P(9) + P(10)

= 10x0.39x0.7 + 0.310

= 0.00014 < 0.05

Since the probability is less than 0.05, it is unusual.

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