A tour bus operator has twenty seats on his bus. He knows that people who have p

Question

A tour bus operator has twenty seats on his bus. He knows that people who have purchased a ticket in advance often do not show up for the tour. Suppose that a person with a ticket fails to show up with probability .10 and that whether or not an individual passenger shows up is independent of the other passengers showing up. This particular tour operator wants to make as much money as he can so he sells 22 tickets for his tour. What is the probability that more passengers with tickets show up than the driver can accommodate? Use a Poisson approximation.

Please show all the work!

Explanation / Answer

here expected number of passenger who do not arrive=np=22*0.1 =2.2

therefore probability that more passengers with tickets show up than the driver can accommodate

=P(at most 1 passeneger does not show up)=(P(X=0)+P(X=1))=(e-2.2*2.20/0!+e-2.2*2.21/1!) =0.1108+.2438 =0.3546

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.