An electronics store researched the TV sales in the last 6 months. The probabili

Question

An electronics store researched the TV sales in the last 6 months. The probability a customer would purchase the Brand 1 model TV was 70% while the rest of the customers purchased the Brand 2 model. Furthermore, 20% of the Brand 1 customers purchased an extended warranty while 40% of Brand 2 customers purchased an extended warranty. A customer is randomly selected from among all those who bought a TV from the store. What is the probability that the selected customer purchased an extended warranty? Round your answer to 2 decimal places.

Explanation / Answer

P(Brand 1 model) = 0.70, P(Brand 2 model) = 0.30

P(Brand 1 with extended warranty) = 0.20, P(Brand 2 with extended warranty) = 0.40

A person is selected at random who could be from brand 1 OR brand 2 model.

P( Extended warranty) = P(Brand 1 model) * P(Brand 1 with extended warranty)  

+ P(Brand 2 model) * P(Brand 2 with extended warranty)

= 0.70 * 0.20 + 0.30 * 0.40

= 0.26

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