Fxercise 10.04 Sell-Test Tutorial Condé Nast Tranlar conducts an annualleyin ata
ID: 3050359 • Letter: F
Question
Fxercise 10.04 Sell-Test Tutorial Condé Nast Tranlar conducts an annualleyin ata b ravorita crise ship. All ships are ratad an a 100-point scala, with highar values indicating hetter sarvica. A sampla of 37 ships that carry fower than S00 passngars resulted in an average rating of 85.3G, and a sample of 43 ships that carry 500 or more passengers provided an average rating ot 81.5. Assume that the population deviation is 4.57 for ships that carry tewer than 500 passengers and 3.93 tor ships that carry 500 or more passengers standard Round your all answers to two decimal places. a whatis the n nt estimate the d merence b twen the population mean rating or ships that cam fe wer than 500 passengers and the m ula on mean rating nr sh s tat cam s oor mnre passengers b. At g5 nonfidence, what is the margin of error c. what is a 95% confidence interval estimate of the difference between the population mean ratings for the two sizes or ships? toExplanation / Answer
Ans:
a)Point estimate for difference of means=85.36-81.5=3.86
b)standard error for difference of mean=sqrt((4.57^2/37)+(3.93^2/43))=0.961
Margin of errror=1.96*0.961=1.88
c)95% CI for difference of means
=3.86+/-1.88
=(1.98, 5.74)
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