In the first part why do we subtract the Probability of (queen and red)? And for
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In the first part why do we subtract the Probability of (queen and red)? And for the second part, can u explain the last step "probability of (21 and PB) = 2/41 =.05 ? How did we get 2 out of 41 Events Not Mutually Exclusive What is the probability of drawing a queen or a red card? Not mutually exclusive Subtract the overlap. Pr(Queen) + Pr(Red) - Pr(Queen and Red) In our Statistics class, what is the probability of being 21 old or choosing a peanut butter cup? . Pr(21)-341 = .07 . Pr(PB)=33/41:80 · Pr(21 and PB) =2/41 =.05 MacBook Air 4 0Explanation / Answer
We have 4 queens - hearts, diamonds, spades and clubs. Hearts and diamonds are red.
we have 26 red card, which also include the 2 red queens.
My favourable outcomes = (Total queens) + (Total Reds), but I am then counting the 2 red queens twice. Hence to balance it out, I subtract them cards ( which are queen and red)
For the second part that is not a value which has been found or calculated. It has been given to you. it says that there are 2 students out of 41, who are both 21 and also like peanut butter.
The question is how many like Peanut Butter or are 21 years old = P(21) + P(PB) - P(21 and PB)
= 3/41 + 33/41 - 2/41 = 34/41
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