Lvdia mathxl.com ADMN 210, Winter 2018, Section 2, MW 4 PM Homework: Homework Ch

Question

Lvdia mathxl.com ADMN 210, Winter 2018, Section 2, MW 4 PM Homework: Homework Chapter 6 Score: 0 of 2 pts 6.2.7-T Lydia Stockar | 2/19/18 422 PM 30f 10 (0 complete) Hw Score: 0%, 0 of 23 Question Help The annual per capita consumption of botted water was 3. 5 galions. Assume that the per cattled water s sprodimately nomaly with a mean of 33.5 and a standard deviation of 12 gallons. a. What is the probability b. What is the probability that someone consumed between 30 and 40 gallons of bottled water? that someone consumed more than 44 gallons of bottled water? d. 90% of people consumed less than how many gallons of bottled water?

Explanation / Answer

Solution:- Given that mean = 33.5 , sd = 12
a. P(X > 44) = P(Z > (X - mean)/sd))
= P(Z > (44 - 33.5)/12)
= P(Z > 0.875)
= 0.1894

b. P(30 < X < 40) = P((30 - 33.5)/12 < Z < (40 - 33.5)/12)
= P(-0.29167 < Z < 0.5417)
= 0.3195

c. P(X < 30) = P(Z < (30 - 33.5)/12)
= P(Z < -0.29167)
= 0.3859

d. percentage = 90%
Z value = -1.645
Lower X value : (X - 33.5)/12 = -1.645
X = -1.645*12 +33.5
X = 13.76

upper X value : X = 53.24
  
  

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