is Question: 1 pl 8 of 16 (7 complete) This Test: 16 pts po Six stand-up comics,
ID: 3046669 • Letter: I
Question
is Question: 1 pl 8 of 16 (7 complete) This Test: 16 pts po Six stand-up comics, A, B, C, D, E, and F, are to perform on a single evening at a comedy club. The order of performance is determined by random selection. Find the probability that a. Comic C will perform fifth b. Comic D will perform first and Comic F will perform last. c. The comedians will perform in the following order. C, D, F, B, A, E. d. Comic A or Comic E will perform third. a. (Type a fraction. Simplify your answer.) b. (Type a fraction. Simplify your answer.) C. (Type a fraction. Simplify your answer.) (Type a fraction. Simplify your answer.) Enter your answer in each of the answer boxes eExplanation / Answer
Since there are 6 comics so number of ways of arranging 6 comics is 6! = 720
(a)
Since comic C need to be on 5th position so for remaining 5 comics we have 5 positions remaining is
5! = 120
So the required probability is
120 / 720 = 1/6
(b)
Since comic D need to be on 1st position and comic F need to be on last position so for remaining 4 comics we have 4 positions remaining is
4! = 24
So the required probability is
24 / 720 = 1/30
(c)
Out of 720 orders there is only one is given order so the required probability is
1 /720
(d)
For third position we have 2 choices, rest 5 comics can be arranged in 5! ways so possible number of arrnagements with A or E on third position is 2 *5! = 240.
The required probability is
240 /720 = 1/3
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