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irefox File Edit View History Bookmarks Tools Window Help com/Student/playerTest aspx?testld 75BBcenterwin yes 162120) https/wwww.mathxi Test Exam 1 This Question: 1 pt A horizontally outstretched arm supports a weight of 22 binahand (see figure). the distance from the shoulder to the ebow is 1 ft (a) The magnitude of the torque about the shoulder is ft-lb. (simplify your answer) (b) The magnitude of the torque about the elbow is t-b. (Simplify your answer) What is the direction of the torque about the shoulderlelbow? O Upward ur O To the left O Out of the screen Click to select your answerts).Explanation / Answer
Torque is given by:
T = rXF = r*F*sin A
A.
torque about the shoulder will be
T = rs*F*sin A
A = 90 deg
rs = 2 ft
F = 22 Lb
T = 2*22*sin 90 deg = 44 lb-ft
B.
torque about the elbow will be
T = re*F*sin A
A = 90 deg
re = 1 ft
F = 22 Lb
T = 1*22*sin 90 deg = 22 lb-ft
C.
Direction = rXF = ixj = k
into the screen
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