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3. A manager wishes to determine whether the mean times required to complete a c

ID: 3046322 • Letter: 3

Question

3. A manager wishes to determine whether the mean times required to complete a certain task differ for the three levels of employee training. He randomly selected seven employees with each of the three levels of training (Beginner, Intermediate and Advanced). The data is summarized in the table.

Beginner

Intermediate

Advanced

20.3

19.3

15.2

19.7

18.4

14.2

27.6

18.1

8.9

25.0

15.9

9.7

25.8

17.8

10.5

26.2

17.0

15.1

20.4

16.8

12.0

T = 165

T = 123.3

T = 85.6

GT = 373.9

a. What are the dependent and independent variables (2 points)

IV:

b. What is the Null hypothesis (in symbols and in words)? (1 point)

c. What is the Research hypothesis (in symbols and in words)? (1 point)

d. Compute the SSbetween, SSwithin, and SStotal. (3 points)

e. Construct the source table? (2 point)

f. What is the conclusion based on this data (don’t forget to include the F-value, etc)? (1 point)

Beginner

Intermediate

Advanced

20.3

19.3

15.2

19.7

18.4

14.2

27.6

18.1

8.9

25.0

15.9

9.7

25.8

17.8

10.5

26.2

17.0

15.1

20.4

16.8

12.0

T = 165

T = 123.3

T = 85.6

GT = 373.9

Explanation / Answer

a) Dependent variable is employee training

and Independent variable is level of trainings

b) Null hypothesis: There is no difference between means of three groups

Alternative hypothesis: There is a difference between means of three groups

alpha:5%

c) To test is there any significance difference between means of three groups

d)  

SSbetween=450.69

SSWithin=115.08

SSTotal=565.77

e) Source table

f) Conclusion:

P value=0.000000596 0.05 we reject the H0. Hence claim is significant.

Anova: Single Factor SUMMARY Groups Count Sum Average Variance Beginner 7 165 23.57143 10.98238 Intermediate 7 123.3 17.61429 1.284762 Advanced 7 85.6 12.22857 6.912381 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 450.6924 2 225.3462 35.24793 5.96E-07 3.554557 Within Groups 115.0771 18 6.393175 Total 565.7695 20
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