A small life insurance company has determined that on the average it receives 6
ID: 3045915 • Letter: A
Question
A small life insurance company has determined that on the average it receives 6 death claims per day. Assuming a Poisson distribution,
a. Find the probability that the company receives seven death claims on a randomly selected day.
b. Find the probability that the company receives at most seven death claims on a randomly selected day. c
. Find the probability that the company receives at least eight death claims on a randomly selected day.
d. Find the probability that the company receives 33 death claims on a randomly selected 5-day work week.
Explanation / Answer
Solution:-
= 6
a) The probability that the company receives seven death claims on a randomly selected day is 0.1377.
x = 7
By applying poisons distribution:-
P(x; ) = (e-) (x) / x!
P(x = 7) = 0.1377
b) The probability that the company receives at most seven death claims on a randomly selected day is 0.744.
x = 7
By applying poisons distribution:-
P(x; ) = (e-) (x) / x!
P(x < 7) = 0.744
c) The probability that the company receives at least eight death claims on a randomly selected day is 0.256.
x = 8
By applying poisons distribution:-
P(x; ) = (e-) (x) / x!
P(x > 8) = 0.256
d) The probability that the company receives 33 death claims on a randomly selected 5-day work week is 0.0599.
= 6 × 5 = 30
x = 33
By applying poisons distribution:-
P(x; ) = (e-) (x) / x!
P(x = 33) = 0.0599
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