327 L01-(Winter Problem Color vision deficiency, commonly known as colorblindnes
ID: 3045293 • Letter: 3
Question
327 L01-(Winter Problem Color vision deficiency, commonly known as colorblindness, is a decreased ability to see color or to distinguish amongst colors. Due to the fact that most genes responsible for colorblindness are found on the X chromosome, males are more likely to be colorblind than females. Suppose, in a particular population, that if a person is male, they have an 8% chance of also being colorblind. If a person is female, they have a 1% chance of also being colorblind. Suppose also that females make up 53% of this particular population. a) Use this information to complete the following contingency table. Not Colorblind Colorblind Row Totals Male Female Column Totals b) A person is randomly selected from this population. What is the probability that they c) A person is randomly selected from this population. What is the probability that they d) Assuming that a randomly-selected person from this population is not colorblind, e) Are the events "male" and "not colorblind" mutually exclusive? Show why/why not are colorblind? are male or colorblind? what is the probability that they are female? using probabilityExplanation / Answer
Solution:
Given,
Probability of being colorblind for a male = 0.08
Probability of being colorblind for a female = 0.01
Probability of picking a female = 0.53
probability of picking a male = 1-0.53 = 0.47
probability of picking a male colorblind = 0.47 * 0.08 = 0.037
probability of picking a non colorblind male = 0.92 * 0.47 = 0.432
probability of picking a female colorblind = 0.53 * 0.01 = 0.005
probability of picking a non colorblind female = 0.99 * 0.53 = 0.524
a)
b) probability of selecting color blind = probability of picking male colorblind + probability of picking female color blind
= 0.037 + 0.005 = 0.042
c) probability of male + probability of female colorblind = 0.47 + 0.005 = 0.475
d) probability of picking a female from noncolor blind = probablity of noncolor blind female / total probability of not colorblinds
= 0.529/ 0.961
= 0.55
e) They are not mutually exclusive because there are 0.432 non color blind males.
Colorblind Not colorblind Row Totals Male 0.037 0.432 0.047 Female 0.005 0.529 0.053 Coulm Totals 0.042 0.961 1Related Questions
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