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8 7 8 5 6 3 Weak Ac ld w con ugaebase Conjugate Acidlweak base ( trong Acid h/we

ID: 304468 • Letter: 8

Question

8 7 8 5 6 3 Weak Ac ld w con ugaebase Conjugate Acidlweak base ( trong Acid h/we ?? bafe , cuear specie smus4 utring baie w/weak acid be in higher cunc) oxidatim-een entloses electrons, O#inded reduction- erement goins electruns O da 42) Which one of the following is the best oxidizing agent? A) Ca B) H2 D) Na E) Li Table 20.2 Half-reaction ) o -Cr0neaus prnduce t cell po -0.74 Fe2+ (aq) 2e- Fe() -0.440 E Fe3+ (aq)e -Fe2+ (s) +0.771 Sn4+ (aq) + 2e-?Sn2+ (aq) | +0.154 Eeduction- E oxidation 43) Which of the following reactions will occur spontaneously as written? A) Sn4 (aq)+ Fe2t (aq) -Sn2 (aq) +Fe (s) B) SnA+ (aq) + Fe3+ (aq) ?Sn2+ (aq) + Fe2+ (aq) C) 3Sn4 (aq)+ 2Cr ()23+ (aq)+ 3Sn2 (aq) D) 3Fe2+ (aq)-Fe (s)+ 2Fe3+ (aq) E) 3Fe (s)+2Cr3+ (aq) -2Cr (s)+3Fe2+ (aq) 44) Which of the following reactions will occur spontaneously as written? Aj 2Cr (s)+3Fe2+ (s)-3Fe (s)+2Cr3+ (aq) Sn2+ (aq)+ Fe2 (s)-Sn4+ (aq)+Fe3+ (aq) C) 2C3+ (aq)+3Sn2+ (aq) -3Sn4+ (aa)+ 2Cr (s) D) Sn4+ (aq) + Fe2+ (s)--Sn2+ (aq) + Fe (s) E) 3Fe2t (aq)+Cr3+ (aq) Cr (s)+3Fe3+ (aq)

Explanation / Answer

42) The reduction potential of the species are as follows;

O2(g) + 4 H+(aq) + 4 e– = 2 H2O; +1.229 V

Ca2+(aq) + 2 e– = Ca(s); -2.87V

Na+(aq) + e– = Na(s); -2.714V

H2(g) + 2 e– = 2 H–(aq); -2.25V

Li+(aq) + e– = Li(s); -3.045V

Among the species mentioned, oxygen has the high reduction potential, hence it can take electrons and act as a reducing agent.

43) The potentials for the species are mentioned below;

Fe2+(aq) + 2 e– = Fe(s); -0.44 V

Sn4+(aq) + 2 e– = Sn2+(aq); +0.15V

Cr ? Cr2+ + 2e-; 0.74 V

Fe ? Fe2+ + 2e-; 0.44V

Cr ? Cr3+ + 3e-; 0.41V

Fe2+  ? Fe3+ + e-; -0.77V        

Fe3+ + e- ? Fe2+; 0.77 V

Among the following options, in case of option D, potentials of both reduction of Fe(II) to Fe and oxidation of Fe(II) to Fe(III) are negative, hence the reaction is spontaneous.

44) Even in this case based on the above explanations, option E is the right option.

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