8 (17 poiots) A 100kg worke pulls a 50kg box borinootally with a constant forre.

Question

8 (17 poiots) A 100kg worke pulls a 50kg box borinootally with a constant forre. The box starts from rest and ben oes 100 m in 10 (a) (3 points) Determine the average velocity of the box during the motion b) (3 prints) Deterie the velocity of the ber after the 10s (Ht fist fuod the arceleration of the bo) te) (3 points) Dra afree body disgran for the boHin there ave fou fos acting on the ho, one of which is friton (d) (3 ponts) The worker pashes with a force of 00 N. Determine the coweth ent of kinetic friction (e) (5 pronts) Determine the amoust of work doue by the work

Explanation / Answer

(a)
Average velocity = 100/10 = 10 m/s

(b)
a = (10 - 0)/10 = 1 m/s^2
Hence,
v = u + at
v = 0 + 1*10 = 10 m/s

(c)
On the box
1) Downwards - a force equal to (mg) or weight is acting
2) Upward - a normal force equal to weight is acting
3) Forwards - Force F in the direction of the motion
4) Backwards - Frictional Force opposite to the firection of motion

(d)
500 - Ff = ma
500 - Mu*50*9.8 = 50*1
Mu = 450/(50*9.8)
Mu = 9/9.8
Mu = 0.918

(e)
Work Done = 500*100 = 50000 J

Related Questions

Navigate

• Browse (All)
• Browse 8
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.