2 Winitob output of binomial probubilties when n TH2 F 0.200000NOKA0 2000co 20 a
ID: 3043941 • Letter: 2
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2 Winitob output of binomial probubilties when n TH2 F 0.200000NOKA0 2000co 20 and p2 BINOMIAL UITH N 20 P 0 200000 PK) 0 0115 0 0576 0.1369 0.2054 0.2182 0.1746 0. 1091 0. 0545 0.0222 0. 0074 0 0020 0 0005 0 0001 K P X LESS OR 0 0 0115 0 0692 0 2061 0 4114 0 6296 0 8042 0 9133 0 9679 0 9900 0 9974 0 9994 0 9999 10 12 1 0000 Notice that we have chosen not to list the probabilities for all values of x 0, 1,2,. n, since the probabilities for all values of x from 13 to 20 are equal to zero, when rounded to four-place decimal accuracy. For all of these values, the cumulative binomial probability, P(x s K), will be equal to 1.0000. Exercises 4.1 A jar contains five balls three red and two white. Two balls are randomly selected without Hint: Compare the characteristics of this experiment with the Basic Techniques replacement from the jar and the number x of red balls is recorded. Explain why x is or is not a binomial random variable. characteristics of a binomial experiment given in Section 4.2.] If the experiment is binomial, give the values of n and p.Explanation / Answer
4.1:
Total number of balls: 3+2 = 5
Since balls are drawn without replacement so the probability of getting red ball will not same for each draw. From example;
The probability of getting a red ball is first draw is
P(red in first red draw) = 3/5
The probability of getting a red ball is second draw is
P(red in second red draw) = 2/5
For a binomial distribution, the probability of success should be remain same for each trial. Each trial should be independent.
Since here trials are not independent because drawn are without replacement. And probability of success does not remain same from trial to trial.
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