Developing an Activity Question about zinc, copper, and iron deleted. I already

Question

Developing an Activity

Question about zinc, copper, and iron deleted. I already answered that one, sorry. The following questions are supposed to be based off of the observation table above.

Summarize the redox reactions that you observed in this investigation. List the reactions in descending order of activity using the data table.

For each reaction in the data table, perform the following steps:

• Write the overall single-displacement reaction.

• Write the half-cell reaction for oxidation.

• Write the half-cell reaction for reduction.

• Add the two half-cell reactions, and write the net ionic equation.

• Identify the reducing agent.

• Identify the oxidizing agent.

After identifying the reaction, use the following format to report the information:

Overall reaction:

Oxidation:

Reduction:

Net ionic reaction:

Reducing agent:

Oxidizing agent:

Observations Fe2 (Feso,) Cu2" (CuSo) Metal Tested Mg2 Number of Reactions Bubbles formed, Mg strip Linted blue and formed black spots, CuSO4 turneda grey color with black spots Hubbles formed quite Didn't notice any reaction quickly. Mg strip rusted. Mg (s) FeSO1 darkened and became cloudy Fe (s) Didn't nolice any reaction Didn'l notice any react Pin devcloped a copper colo 0 Cu (s) Didn't notice any reaction Didn't notice any reaction Didn't notice any reaction

Explanation / Answer

FOLLOWING ARE THE REDUCTION POTENTIAL VALUES WHICH GOVERN THE REACTIONS:

Mg2+ -->Mg( E0=-2.372 V)

Fe2+-->Fe( E0 =-0.44V)

Cu2+ -->Cu( E0 =+0.337 V)

CASE 1: Mg with FeSO4 :

Overall reaction: Mg + FeSO4 = MgSO4 + Fe

Oxidation: Mg0 - 2 e- = Mg2+

Reducton: Fe2+ + 2e- = Fe0

Net ionic reaction: Mg0 + Fe2+ = Mg 2++ Fe0

Reducing agent: Mg(s) (it reduceses Fe 2+ to Fe 0)

Oxidizing agent:FeSO4 (it oxidized Mg0 t Mg2+)

CASE 2: Mg in CuSO4 :

Overall reaction: Mg + CuSO4 = MgSO4 + Cu

Oxidation: Mg0 -2e = Mg 2+

  Reduction: Cu2+ + 2e = Cu0

   Net ionic reaction : Mg0 + Cu2+ = Mg2+ + Cu0

  Reducing agent: Mg(s)

Oxidizing agent: CuSO4

CASE 3: Fe with CuSO4 :

Overall reaction: Fe + CuSO4 = FeSO4 + Cu

Oxidation: Fe0 - 2 e- = Fe2+

Reducton: Cu2+ + 2e- = Cu0

Net ionic reaction: Fe0 + Cu2+ = Fe 2++ Cu0

Reducing agent: Fe(s) (it reduceses Cu 2+ to Cu 0)

Oxidizing agent:CuSO4 (it oxidized Fe0 to Fe2+)

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.