23. Dining Out In a sample of 1000 U.S. adults, 180 dine out at a restaurant mor

Question

23. Dining Out In a sample of 1000 U.S. adults, 180 dine out at a restaurant more than once per week. Two U.S. adults are selected at random without replacement. (Adapted from Rasmussen Reports) (a) Find the probability that both adults dine out more than once per (b) Find the probability that neither adult dines out more than once (c) Find the probability that at least one of the two adults dines out more (d) Which of the events can be considered unusual? Explain. week. per week. than once per week.

Explanation / Answer

Solurion:- Probability one adult will dine out more than once a week is 180/1000

a) Probability both selected will dine out more than once a week is (180/1000)*(179/999) = 0.032

b) Probability neither dines out is (820/1000)*(819/999) = 0.672

c) Probability at least one should be the complement of 1 -  0.672 = 0.328

d) The event in part (a) is unusual because its probability is less than or equal to 0.05

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