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23. A sample of 99 distances has a mean of 24 feet and a median of 24.5 feet. Un

ID: 1710770 • Letter: 2

Question

23. A sample of 99 distances has a mean of 24 feet and a median of 24.5 feet. Untortunately, it has just been discovered that an observation which was erroneously recorded as "30 actually had a value of "35". If we make this correction to the data, then: (a) the mean remains the same, but the median is increased (b) the mean and median remain the same (c) the median remains the same, but the mean is increased (d) the mean and median are both increased (e) we do not know how the mean and median are affected without fur- ther calculations; but the variance is increased. 24. The term test scores of 15 students enrolled in a Business Statistics class were recorded in ascending order as follows: 4,7’ 7, 9, 10, 11, 13, 15, 15, 15, 17, 17, 19, 19, 20 After calculating the mean, median, and mode, an error is discovered: one of the 15's is really a 17. The measures of central tendency which will change are: (a) the mean only (b) the mode only (c) the median only (d) the mean and mode (e) all three measures 25. Suppose a frequency distribution is skewed with a median of $75.00 and a mode of $80.00. Which of the following is a possible value for the mean of distribution? (a) $86 (b) $91 (c) $64 d) 57s e-None of these 2006 Carl James Schwars

Explanation / Answer

Q.23

ans =(C) median is mid value so it would be remains same in given range

while mean =average value so it would incrase by increasing the Sum of values.

Q24 d

average value increse so mean increase

and frequency of 17 becomes 3 so mode change

median reamains same because 15 is after mid point

Q25 e

mode =3median-2mean

so mean=(3x75-80)/2=72.5

Q26 d

by arrenging the given values order is

L,4.5,5.2,5.5,(6.0),8.7,8.9,H,H we found median =6.00

Q27 a

Q 28 not complet visivle

Q31 c

Q32 d

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