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Moving to another question will save this response. | Question 5 of 10 > » Question 5 0.4 points Save Answer Adriana, Kevin and Gabriel fill orders in a fast food restaurant. Adriana fills 42% of all orders received Kevin fils 25% and Gabriel fils the remaining ones. Adriana incorrectly fills 8% of the orders she take, Kevin incorrectly fills 4% of the orders he takes, and Gabriel incorrectly fills 5% of the orders he takes What is the probability that a randomly selected order has been correctly filled by Adriana? (USE 3 DECIMALS Moving to another question will save this response. Question 5 of 10

Explanation / Answer

Q5. Adriana takes 42% orders = 0.42 probability of taking order

Probability that Adriana fills wrong order = 8% of what she takes

= 8*42/100 = 3.36% (=> 0.036 overall probability)

Probability of Adriana filling right order = 0.42 – 0.036 =0.384

Q2.

Given: p = 0.58

P’ = 375/660 = 0.568

Z = (p’ – p)/ sqrt(p(1-p)/n)

= (0.568-0.58)/sqrt(0.58*(1-0.58)/660)

= -0.012/0.0192

Z= -0.62

Thus P(defective bottles > 375) = P(Z> -0.62)

= 0.73

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