Scare: 0.43 of 1 pt 7.5.19 Question Help A snack food manufacturer estimates tha

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Scare: 0.43 of 1 pt 7.5.19 Question Help A snack food manufacturer estimates that the variance of the number of grams of carbohydrates in servings of its tortilla chips is 1.17. A dietician is asked to test this claim and finds that a random sample of 24 servings has a variance of 1.15. At e below. =0.05, is there enough evidence to reject the manufacturer's daim? Assume the population is normally distributed. Complete parts a through (a) Write the claim mathematically and identify Hp and Ha OA. Ho : 2s 1.17 (Claim) Ha : 2> 1.17 Ho:2+1.17 Hay? Hoy?, e 1.17 (Claim) Hay?#1.17 B. O D. Ho:221.17 C. 1.17 (Claim) Ha:2 1.7 (Claim) (b) Find the critical value(s) and identify the rejection region(s). The critical value(s) is(are) 11.689, 38.076 (Round to three decimal places as needed. Use a comma to separate answers as needed.) Choose the correct statement below and fill in the corresponding answer boxes. 1. O A. The rejection region is 2 O B. The rejection regions are , O C. The rejection region is x2>. and X2 >

Explanation / Answer

Since the critical values are 11.680 and 38.076 for two Tailed test.

The rejection regions are

Chi square < 11.680 and

Chi square > 38.076

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