Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Scandium fluoride,ScF3, ispractically insoluble. a) Calculate thesolubility of S

ID: 679928 • Letter: S

Question

Scandium fluoride,ScF3, ispractically insoluble.

a) Calculate thesolubility of ScF3 in pure water. You may neglect the hydrolysis of thefluoride

ion as it has a negligibleimpact on the overall solubility.

b) Calculate theconcentrations of all aqueous species in a saturated solution ofScF3.

c) Scandium fluoride issomewhat more soluble in acidic solution. Determine the molarsolubility

of ScF3 in 1.00M HNO3.

d) Scandium fluoride issomewhat less soluble in the presence of NaF. Determine themolar

solubility of ScF3 in 0.050M NaF.

Explanation / Answer

        We Know that: (a)        ScF3 -----> Sc+3  + 3 F-          If we ignorethe solubility of F- .          The Kspof ScF3   = Solubility of Sc+3            Solubilityof Sc+3   = 4.2 x 10^-18 M     (b)          The Conc .all the aqueous ions of ScF3 is            Sc+3   = 4.2 x 10^-18 M              3F - = 12.6 x 10 ^ -18 M     (c)              ScF3 + 3 HNO3 --------> Sc (NO3)3  + 3 HF              Solubility of ScF3 = ( Ksp / 27)1 / 4                                            = 1.9859 x 10-5 M      (d)           ScF3   + NaF ------> Sc+3   + 3 F-                                                  S           3S +0.050                Ksp = S ( 3S + 0.050 ) 3                  By Solving the above equation we get :                    S = 3.36 x 10-14 M (a)        ScF3 -----> Sc+3  + 3 F-          If we ignorethe solubility of F- .          The Kspof ScF3   = Solubility of Sc+3            Solubilityof Sc+3   = 4.2 x 10^-18 M     (b)          The Conc .all the aqueous ions of ScF3 is            Sc+3   = 4.2 x 10^-18 M              3F - = 12.6 x 10 ^ -18 M     (c)              ScF3 + 3 HNO3 --------> Sc (NO3)3  + 3 HF              Solubility of ScF3 = ( Ksp / 27)1 / 4                                            = 1.9859 x 10-5 M      (d)           ScF3   + NaF ------> Sc+3   + 3 F-                                                  S           3S +0.050                Ksp = S ( 3S + 0.050 ) 3                  By Solving the above equation we get :                    S = 3.36 x 10-14 M                  By Solving the above equation we get :                    S = 3.36 x 10-14 M
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote