Eye color is determined genetic combination. Let R represent the gene for brown
ID: 3038700 • Letter: E
Question
Eye color is determined genetic combination. Let R represent the gene for brown eyes and l represent the gene for blue eyes. Any gene combination including R results in brown eyes. Consider the offspring of a parent with a homozygous brown-eyed, RR, gene combination and a parent with a heterozygous brown-eyed, Rl, gene combination. Show how you could use a polynomial to model the possible genetic combinations of the offspring. What percent of the possible genetic combinations result in brown-eyed offspring? What percent of the possible genetic combinations arc earners for the blue-eyed gene? Fill in the Punnett square below to model your conclusions.Explanation / Answer
Answer 1: RR + RR + RI + RI (As explained below)
Total combinations = [parent][parent] = [R + R][R + l] = 2R[R+I] = 2R2 + 2RI = 2RR + 2RI = RR + RR + RI + RI
Answer 2: 100% (As explained below)
Since the problem states that any gene combination including R results in brown eyes, we need to count for all combinations having the allele R. All 4 out of 4 possible combinations have R and so, the probability is 100%.
Answer 3: 50% (As explained below)
All combinations having I will be carriers for I. There are 2 out of 4 possible combinations having an I. So, the probability is 50%.
Answer 4: Punnett Sqaure will be as below:
R R R RR RR I RI RIRelated Questions
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