scenario: Your children\'s museum isgowing and schools from al over southern Mda
ID: 3035837 • Letter: S
Question
Explanation / Answer
The formula for computing the equated monthly installment is EMI = P[ r(1+r)n]/[ (1+r)n -1] where P is the amount of loan, r is the monthly rate of interest in decimals and n is the number ofmonthly installments.
A). For the 1st loan, P = $ 82,000, r = (6.5/100)*1/12 = 6.5/1200 and n = 12*12 = 144
Then the EMI = 82000[(6.5/1200)*(1+6.5/1200)144]/[(1+6.5/1200)144-1] = 444.167(1206.5/1200)144/[(1206.5/1200)144-1] = 444.167(2.17688531/1.17688531) = 444.167*1.849700469 = $ 821.58( on rounding off to the nearest cent). The total amount repaid is $ 821.58 *144 = $118307.52 so that the amount of interest is 118307.52-82000 = $ 36307.52
B) For the 2nd loan, P = $ 82,000, r = (2.75/100)*1/12 = 2.75/1200 and n = 7*12 = 84
Then the EMI = 82000[2.75/1200*(1+2.75/1200)84]/[(1+2.75/1200)84-1] = 187.9167(1202.75/1200)84/[(1202.75/1200)84-1] = 187.9167(1.212009546/0. 212009546) = 187.9167*5.716768744= $1074.28 ( on rounding off to the nearest cent). The total amount repaid is $ 1074.28 *84 = $90239.52 so that the amount of interest is90239.52-82000 = $ 8239.52
C) the EMI for the 1st and the 2nd loans are $ 821.58 and $1074.28 respectively and the interest paid obn the loan are $ 36307.52 and $ 8239.52 respectively.
D) If the museum can afford a higher installment , then the 2nd loan would be more cost-effective.
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