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saplinglearning.com/ibiscms/mod/ibis/view.php?id-6284937 Jump Sapling Learning Map d During exercise when the body lacks an adequate supply of oxygen to support energy production, the that is produced from the breakdown of glucose is converted into lactate. High lactate levels can to acidity in the muscle cells as some of the lactate hydrolyzes to lactic acid. The dissociation of lactic acid to lactate is shown in the reaction below Lactic acid has a pK, of 3.86. Lactic Acid Lactate A solution containing a mixture of lactic acid and lactate was found to have a pH of 4.26. Calaulate the ratio of the lactate concentration to the lactic acid concentration in this solution. Number lactate lactic acid Tools O Previous Give Up & View Solution Check Answer Next Ex 9Hint about us careersprivacy policy terms of use sontect us hel rch

Explanation / Answer

1)

Answer

[lactate] /[lactic acid] = 2.512

Explanation

Henderson-Hasselbalch equation is

pH = pKa + log([A-] / [HA])

pKa of lactic acid = 3.86

[A-] = [lactate]

[HA] = [lactic acid]

pH = 4.26

Therefore

4.26 = 3.86 + log([lactate] /[lactic acid])

log([lactate] /[lactic acid]) = 0.40

[lactate] /[lactic acid] = 1×100.40 = 2.512

2)

a)

Answer

pH = 6.68

Explanation

pH = - log[H+] = - log(2.1×10-7) = 6.68

b)

Answer

[OH-] = 4.76×10-8 M

Explanation

Ionic product of water, Kw = 1.00×10-14M2

   [H+] [OH-] = 1.00×10-14M2

2.1 ×10-7M × [OH-] = 1.00×10-14M2

[OH-] = 1.00×10-14M2/2.1×10-7M

[OH-] = 4.76×10-8M

c)

Answer

Ka = 7.5×10-7

Explanation

Ka = [H+] [A-] /[HA]

Ka = (3.00×10-4M) (3.00×10-4M) / 0.120M

Ka = 7.5×10-7

  

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