I Just need help with just #4!!!!!!!!!!!!!! Answer for the #4 is 28 percent, But
ID: 302106 • Letter: I
Question
I Just need help with just #4!!!!!!!!!!!!!! Answer for the #4 is 28 percent, But I don't know how to get there, I need an clear explanation Please!!!!!!!
FOr number #3 Answers are
NEE for the tropical pasture is - 262 g C/m2/year, and negative sign indicates that it is source for CO2.
2,345 g C/m/year - 2,606 g C/m2/year= - 262 g C/m2/year
NEE For the second-growth forest is 442 C/m2/year, and the value being positive indicates that it is acting as Sink.
2,082 g C/m2/year - 1,640 C/m2/year= 442 C/m2/year
#4 Reduce the both value to half, and you get
0.5 (- 262 g C/m2/year) + 0.5 (442 g C/m2/ year) = 90 g C/m2/year
(442 C/m2/year- 90 g C/m2/year)/( 442 C/m2/year)=80% C/m2/year
which is This is an 80% reduction in NEE by tropical rainforests,
I need the steps for get to 28% reduction in C uptake by the terrestrial land surface.!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Explanation / Answer
3rd part
NEE for tropical pasturee = 2345-2606
= -261g C/m2/year
NEE For the second-growth forest is 442 C/m2/year, and the value being positive indicates that it is acting as Sink.
2,082 g C/m2/year - 1,640 C/m2/year= 442 C/m2/year
4th part
reduce both values to half
=0.5 (- 261g C/m2/year) + 0.5 (442 g C/m2/ year) =-130g C/m2/year+221g C/m2/year
= 90g C/m2/year
now
as the production will be decreased to half if half of tropical forests are converted into pastures
(.5*442 C/m2/year- 90 g C/m2/year)/( 442 C/m2/year)=(221 C/m2/year- 90 g C/m2/year)/( 442 C/m2/year)
= 131/442
=0.296 * 100
29.6%
so approximately in round figure we may say 28 % depending on the values
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.