1. A sample of n =16 scores is obtained from a population with m=70 and theta=20

Question

1. A sample of n =16 scores is obtained from a population with m=70 and theta=20 if the sample mean is M = 75 then the z score corresponding to The sample mean is
A.z=1.00 B.z=0.50 C.z=2.00 D.z=0.25
2. A random sample of n = 4 scores is selected from a normally distributed population with u=80 and theta=12 what is the probability that the sample mean will be greater than 86? A. 0.0668 B. 0.3085 C. 0.0228 D. 0.1587 Please explain 1. A sample of n =16 scores is obtained from a population with m=70 and theta=20 if the sample mean is M = 75 then the z score corresponding to The sample mean is
A.z=1.00 B.z=0.50 C.z=2.00 D.z=0.25
2. A random sample of n = 4 scores is selected from a normally distributed population with u=80 and theta=12 what is the probability that the sample mean will be greater than 86? A. 0.0668 B. 0.3085 C. 0.0228 D. 0.1587 Please explain
A.z=1.00 B.z=0.50 C.z=2.00 D.z=0.25
2. A random sample of n = 4 scores is selected from a normally distributed population with u=80 and theta=12 what is the probability that the sample mean will be greater than 86? A. 0.0668 B. 0.3085 C. 0.0228 D. 0.1587 Please explain

Explanation / Answer

1)

Z = [M - m] / [ theta / srqt( n) ]

Z = [75 - 70 ] / [ 20 / srqt(16) ]

Z = 1.00

2)

P( x > 86 )

P( z > [86-80] / [12 / srqt(4)] )

P( z > 1 ) = 0.1587

using tables of normal distribution you will find the probabilitiy of P( z > 1) that is 0.1587

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