The rivet group shown in Fig. P.12.4 connects two narrow lengths of plate one of

Question

The rivet group shown in Fig. P.12.4 connects two narrow lengths of plate one of which carries a 15 kN load positioned as shown. If the ultimate shear strength of of a rivet is 350 N/mm^2 and its failure strength in compression is 600 N/mm^2, determine the allowable values of rivet diameter and plate thickness.

MY PROGRESS SO FAR:

(1) vertical shear on each rivet: 15kN/9 rivets = 1.667 kN

(2) the moment on the rivet group is 15 kN x 50 mm = 750 kN*mm

(3) the distance of rivets 1, 3, 7, and 9 from the centroid (rivet 5) is sqrt( (25^2) + (25^2) ) = 35.355 mm

(4) since the distance from rivets 2, 4, 6, and 8 to rivet 5 is 25 mm each, SUM(r^2) = 4(1,250) + 4 (625) = 7,500 mm^2

          (i) since 25^2 = 625 and 35.355^2 = 1,250

(5) so the shear forces on rivets 1, 3, 7, and 9 due to the moment are S = (750/7,500) x 35.355 = 3.5355 kN

(6) and teh shear forces on rivets 2, 4, 6, and 8 due to the moment are S = (750/7,500) x 25 = 2.5 kN

ANSWERS:

The rivet diameter is 4.2 mm, plate thickness is 1.93 mm.

I WOULD LIKE YOU TO SHOW AS MUCH WORK AS POSSIBLE PLEASE I DONT HAVE THIS PROBLEM WORKED OUT 100%

The rivet group shown in Fig. P.12.4 connects two narrow lengths of plate one of which carries a 15 kN load positioned as shown. If the ultimate shear strength of of a rivet is 350 N/mm^2 and its failure strength in compression is 600 N/mm^2, determine the allowable values of rivet diameter and plate thickness. MY PROGRESS SO FAR: vertical shear on each rivet: 15kN/9 rivets = 1.667 kN the moment on the rivet group is 15 kN x 50 mm = 750 kN*mm the distance of rivets 1, 3, 7, and 9 from the centroid (rivet 5) is sqrt( (25^2) + (25^2) ) = 35.355 mm since the distance from rivets 2, 4, 6, and 8 to rivet 5 is 25 mm each, SUM(r^2) = 4(1,250) + 4 (625) = 7,500 mm^2 since 25^2 = 625 and 35.355^2 = 1,250 so the shear forces on rivets 1, 3, 7, and 9 due to the moment are S = (750/7,500) x 35.355 = 3.5355 kN and teh shear forces on rivets 2, 4, 6, and 8 due to the moment are S = (750/7,500) x 25 = 2.5 kN ANSWERS: The rivet diameter is 4.2 mm, plate thickness is 1.93 mm. I WOULD LIKE YOU TO SHOW AS MUCH WORK AS POSSIBLE PLEASE I DONT HAVE THIS PROBLEM WORKED OUT 100%

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