full answer For the pinion and gear shown below. Assume the tooth forms are stan

Question

full answer

For the pinion and gear shown below. Assume the tooth forms are standard AGMA full -depth involute profiles, and a 6 pd, 20degree pressure angle, phi, 19-tooth pinion. Np is meshed with a 37-tooth gear. Ng. Calculate the following : The gear ratio, mr, and the velocity ratio mv. The circular pitch pc The base pitch pb. The pitch diameters. dg and dp. The pitch radii, rg and rp. The center distance. C. The addendum, a and the dedendum, d. The whole depth, h,. The clearance, c. The circular tooth thickness. The outside diameters. dog and dop. The contact ratio of the gear set.

Explanation / Answer

Given

Np = 19

Ng = 37

a) Gear Ratio = wp/wg = Ng/Np = 37/19 = 1.95

Velocity ratio = Ng/Np 1.95

b)Circular Pitch = Pi/Pd = 3.14/6 = 0.523

c)Base Pitch = cir.pitch*Cos(pressure angle) = 0.523*cos(20) = 0.492

d)Pd = N/d

Diameter of gear(dg) = Ng/Pd = 37/6 = 6.167

Diameter of Pinion(dp) = Np/Pd = 19/6 = 3.167

e) rg = dg/2 = 3.084

rp = dp/2 = 1.584

f)C = rp+rg = 4.668

g) module, m = dg/Ng = 6.167/37 = 0.167

addendum,a = m = 0.167

Dedendum,d = 1.157*m = 0.193

h)hi = a+d = 0.360

i)clearance,c = d-a = 0.026

j)Tooth Thickness

t = Pi*d/N = 3.14/6 = 0.523

k)do = 2/pd +d

dog= 2/6 + 6.167 = 6.5

dop = 2/6 + 3.167 = 3.5

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