Please read carefully, as I have my own calculations and I am looking for an ans

Question

Please read carefully, as I have my own calculations and I am looking for an answer that is correct. Please do not rush your answer, I will only give the stars that is deserved. Please show workings.

A small eyelet anchor is shown in figure 5. The centre of the loop (eg where the x-y axis is shown) is 50 mm away from the timber surface into which it is fastened. Three tension wires are attached to the loop as shown in figure 5 and the line of action of each force passes through the centre of the loop.

Determine the horizontal component and vertical component of the reaction force and determine the reaction moment that the timber base must exert on the anchor at the point where the two meet.

Explanation / Answer

Horizontal component of reaction force = [23 * sin(30) ] + [15.5 * sin(45)] = 22.4602 kN

Vertical component of reaction force = [23 * cos(30) ] - [15.5 * cos(45)] - 18.5 = -9.5416 kN

Reaction moment = r x F = (vertical force * radius of eyelet * sin(90)) + (horizontal force * radius of eyelet * sin(0))

= (vertical force * radius of eyelet)

= -9.5416 * (50/1000) = -0.47707 Nm

=> Reaction moment = 0.47707 Nm in ( negative z direction)

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