A player of a video game confronted with a series of four opponents and an %80 p

Question

A player of a video game confronted with a series of four opponents and an %80 probability of defeating each opponent.Assume that the results from opponents are independent (and that when the player is defeated by an opponent the game ends).

a)what is the probability that a player defeats all four opponents in a game ?

b)what is the probability that a player defeats at least two opponents in a game ?

c) if the game is played three times, what is the probability that the player defeats all four opponents at least once?

Explanation / Answer

a) .8*.8*.8*.8 = 0.4096 b) 0.8*0.8 = 0.64

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.