The number of electricaloutages in a city varies from day to day. Assume that th

Question

The number of electricaloutages in a city varies from day to day. Assume that the number ofelectrical outages (x) in the city has the following probabilitydistribution.

x f(x) 0 0.80 1 0.15 2 0.04 3 0.01
The mean and the standard deviation for the number of electricaloutages (respectively) are x f(x) 0 0.80 1 0.15 2 0.04 3 0.01 When sampling withoutreplacement, the probability of obtaining a certain sample is bestgiven by a The number of electricaloutages in a city varies from day to day. Assume that the number ofelectrical outages (x) in the city has the following probabilitydistribution.

x f(x) 0 0.80 1 0.15 2 0.04 3 0.01
The mean and the standard deviation for the number of electricaloutages (respectively) are 2.6 and5.77 0.26 and0.577 3 and0.01 0 and0.8

Explanation / Answer

so 0*.80 + 1*.15 + 2*.04 + 3*.01 = .26 The standard deviation of a probability distribution is thesquare root of( (summation of (x^2*p(x))) -mean^2) so 0*0*.80 + 1*1*.15 + 2*2*.04 + 3*3*.01 = .4 .4 - (mean)^2 = .4 - (.26)^2 = .4 - .0676 = .3324 Square root of .3324 = .57654 So the answer is .26 and .577
The hypergeometric distribution is a discrete probabilitydistribution that describes the number of successes in a sequenceof n draws from a finitepopulation WITHOUT replacement http://en.wikipedia.org/wiki/Hypergeometric_distribution
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