Please help me figure out this... A researcher is testing the effectiveness of a

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Please help me figure out this...
A researcher is testing the effectiveness of a new herbalsupplement that claims to improve memory performance. A sample of n= 25 college students is obtained and each student takes thesupplement daily for six weeks. At the end of the 6-week period,each student is given a standardized memory test, and the averagescore for the sample is M = 39. For the general population ofcollege students, the distribution of test scores is normal with amean of = 35 and a standard deviation of =15. Dostudents taking the supplement have significantly better memoryscores? Use a one-tailed test with = .05 Please help me figure out this...
A researcher is testing the effectiveness of a new herbalsupplement that claims to improve memory performance. A sample of n= 25 college students is obtained and each student takes thesupplement daily for six weeks. At the end of the 6-week period,each student is given a standardized memory test, and the averagescore for the sample is M = 39. For the general population ofcollege students, the distribution of test scores is normal with amean of = 35 and a standard deviation of =15. Dostudents taking the supplement have significantly better memoryscores? Use a one-tailed test with = .05

Explanation / Answer

n=25, X-bar=39 =35, =15 Z(0.05)=1.645 (check normal table) The test hypothesis is Ho:35 The test statistics is Z=(X-bar -)/(/n)=(39-35)/(15/25)=1.33 Since Z=1.33

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