Acrossover trial is conducted to compare an experimental medicationfor migraine

Question

Acrossover trial is conducted to compare an experimental medicationfor migraine headaches to a currently available medication. Atotal of 50 patients are enrolled in our study and each patientreceives both treatments. The outcome is the time , inminutes, until the headaches pain resolves. Following eachtreatment, patients record the time it takes until pain isresolved. Treatments are assigned in random order (i.e.,some patients receive the currently available medication first andthen the experimental medication, and others receive theexperimental medication) The mean differences in times betweenthe experimental and currently available medication is -9.4 minuteswith a standard deviation of 2.6 minutes. Construct a 95% CIfor the mean difference in times between the experimental andcurrently available medication

Explanation / Answer

First I will list the given info: n=50 mean difference = -9.4 st dev = 2.6   I am assuming this is the standarddeviation computed by the formula. Most likely given 95% CI So then the formula to use is CI= mean (+/-) t* (st. dev.) CI=-9.4 - (2.021)(2.6) = (-14.6546, -4.1454) I hope you find this helpful. If you need any more help feel freeto message me.

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