1. What is the probability that a randomly selected day from 2013 will have a Gr

Question

1. What is the probability that a randomly selected day from 2013 will have a Group Trades total within 59000 of the mean?

- mean equal 3421439

- standard deviation equal 508638.08

2. How many standard deviations below the mean was the Group Trades for July 29?

It is _________ standard deviations below the mean. (NOTE: The wording of the question means your answer should NOT be negative. Enter your answer rounded to 4 decimal places.)

- mean equal 3421439

- standard deviation equal 508638.08

-  Group Trades for July 29 - 3012457

Explanation / Answer

Mean = 3421439

S.D. = 508638.08

P(3421439 -59000 < X < 3421439 +59000)

P(3362439 < X < 3480439)

Z score at x = 3362439

Z = (X - ?) / ?
Z = (3362439 - 3421439) / 508638

Z = -0.116

Z Score at x =  3480439

Z = (X - ?) / ?
Z = (3480439 - 3421439) / 508638

Z = 0.116

P(3362439 < X < 3480439) = P ( -0.166 < Z < 0.166) =  0.0923

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