Explain results using -p value method. Does the null hypothesis get rejected at

Question

Explain results using -p value method. Does the null hypothesis get rejected at 5% of significance level?
Explain result with confidence intervals. (Use 95% of confidence level). This should corroborate result in 1, and, if there is, identify which one in the population is different.
Is there an area that has a lesser mean in calls? Explain. To measure if there are differences in the cost of telephone service within its areas, P&G; evaluates the mean time of minutes of calls to the street in 5 areas of the firm. The time of telephone calls taken from 7 workers of each area is presented in this table Logistics Marketing Sales Management Production 0.6 2.2 12.3 4.2 2.8 1.4 4.3 6.3 1.2 3.1 2.5 0.6 5.1 5.2 1.7 2.9 4.4 2.6 26.6 1.2 1.9 3.8 1.6 0.4 7.4 1.4 14.2 7 8.4 2.6 0.8 Anova: Single Factor SUMMARY Groups Logistica Marketing Ventas Gerencia Produccion Count Sum Average Variance 7 10.4 1.485714 1.314762 7 53.6 7.657143 75.18619 7 41.5 5.928571 19.80238 7 19.5 2.785714 3.178095 7 27.8 3.971429 15.33571 ANOVA Source of Variation MS P-value F crit Between Groups 169.556 442.389 1.845935 0.146072 2.689628 Within Groups 688.9029 30 22.96343 Total 858.4589 34

Explanation / Answer

The decision rule for p value is,

i) if p value > 0.05 accept null hypothesis

ii) if p value < 0.05 reject null hypothesis

here the p value = 0.146072

so , p value > 0.05 singnificant level . so accept the null hypothesis.

the confidence interval for the mean are,

all means are in the 95% confidence interval.

c) our hypothesis is accepted so it means no lesser mean calls in any area all are same.

from the accepted p value it shows there is no difference in cost of telephone service within its areas.

(1.105835 ,10.77988) (4.784437, 56.47271) (4.454289 ,42.97428) (2.195098, 20.09062) (2.674028, 29.0974)

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