A random sample of 46 adult coyotes in a region of northern Minnesota showed the
ID: 2947939 • Letter: A
Question
A random sample of 46 adult coyotes in a region of northern Minnesota showed the average age to be x = 2.03 years, with sample standard deviation s = 0.78 years. However, it is thought that the overall population mean age of coyotes is ? = 1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use ? = 0.01.
(a) What is the level of significance?
State the null and alternate hypotheses.
H0: ? < 1.75 yr; H1: ? = 1.75 yrH0: ? = 1.75 yr; H1: ? ? 1.75 yr H0: ? > 1.75 yr; H1: ? = 1.75 yrH0: ? = 1.75 yr; H1: ? > 1.75 yrH0: ? = 1.75 yr; H1: ? < 1.75 yr
(b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution.
The standard normal, since the sample size is large and ? is known.The Student's t, since the sample size is large and ? is known. The Student's t, since the sample size is large and ? is unknown.The standard normal, since the sample size is large and ? is unknown.
What is the value of the sample test statistic? (Round your answer to three decimal places.)
(c) Find the P-value. (Round your answer to four decimal places.)
Explanation / Answer
The statistical software output for this problem is:
One sample T summary hypothesis test:
? : Mean of population
H0 : ? = 1.75
HA : ? > 1.75
Hypothesis test results:
Hence,
a) Level of significance = 0.01
Hypotheses: H0: ? = 1.75 yr; H1: ? > 1.75 yr
b) The Student's t, since the sample size is large and ? is unknown.
Test statistic = 2.435
c) P - value = 0.0095
Mean Sample Mean Std. Err. DF T-Stat P-value ? 2.03 0.11500473 45 2.4346826 0.0095Related Questions
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