what\'s the sum of the digits of (10 ^( (4n^2) +8)+1) 2 if 14 times a natural nu

Question

what's the sum of the digits of (10 ^( (4n^2) +8)+1)2 if 14 times a natural number has a units digit of 2 whenexpressed in base 12, what is the units digit of the natural numberwhen expressed in base 6? what's the sum of the digits of (10 ^( (4n^2) +8)+1)2 if 14 times a natural number has a units digit of 2 whenexpressed in base 12, what is the units digit of the natural numberwhen expressed in base 6? if 14 times a natural number has a units digit of 2 whenexpressed in base 12, what is the units digit of the natural numberwhen expressed in base 6?

Explanation / Answer

CRAMSTER POLICY IS 1 Q PERPOST
ANSWERING Q2
POST Q1 SEPARATELY

Question Details: what's the sum of the digits of (10 ^( (4n^2) +8)+1)2 ==============================
if 14 times a natural number has a units digit of 2 when expressedin base 12, what is the units digit of the natural number whenexpressed in base 6?
LET THE NUMBER BE X
14 times a natural number has a units digit of 2 when expressed inbase 12...THAT IS
14X=2 [MOD 12] = 2+ 12 P
WHERE P IS AN INTEGER
14X=2 [MOD 12] = 2+ 12 P =2+6*2P= 2+6Q=2[MOD 6]
SINCE 2<6 THE ANSWER IS THAT WE WILL STILL HAVE 2 IN THE UNITSPLACE
WHEN THE NUMBER X IS EXPRESSED IN BASE 6

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if 14 times a natural number has a units digit of 2 when expressedin base 12, what is the units digit of the natural number whenexpressed in base 6?
LET THE NUMBER BE X
14 times a natural number has a units digit of 2 when expressed inbase 12...THAT IS
14X=2 [MOD 12] = 2+ 12 P
WHERE P IS AN INTEGER
14X=2 [MOD 12] = 2+ 12 P =2+6*2P= 2+6Q=2[MOD 6]
SINCE 2<6 THE ANSWER IS THAT WE WILL STILL HAVE 2 IN THE UNITSPLACE
WHEN THE NUMBER X IS EXPRESSED IN BASE 6

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