what volume of sulfur dioxide gas at 45 c and 723 mmHg will react completely wit

Question

what volume of sulfur dioxide gas at 45 c and 723 mmHg will react completely with 0.870 of oxygen gas at constant temperature and pressure?
2 SO2(g)+O2(g) -> 2SO3(g) what volume of sulfur dioxide gas at 45 c and 723 mmHg will react completely with 0.870 of oxygen gas at constant temperature and pressure?
2 SO2(g)+O2(g) -> 2SO3(g) what volume of sulfur dioxide gas at 45 c and 723 mmHg will react completely with 0.870 of oxygen gas at constant temperature and pressure?
2 SO2(g)+O2(g) -> 2SO3(g)

Explanation / Answer

0.870 of what

I start calculation with 0.87 Moles of oxygen

2 SO2(g) + O2(g) = 2 SO3(g)

According to equation 0.87 Moles of oxygen needs (0.87 x 2 = 1.74) 1.74 Moles of SO2

Then we have to calculate the volume for 1.74 Moles of SO2

PV = n RT

P = 723 mm Hg or 0.9513 atm

V= ?

n = 1.74

R = Gas constant 0.0821 L atm K-1 Mol-1

T = 273 + 45 = 318 K

Substitute in the equation and find V

0.9513 x V =   1.74 x 0.0821 x 318

V = 47.75 Liter of SO2 needs

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