It is assumed that the mean systolic blood pressure is = 120 mm Hg in the genera

Question

It is assumed that the mean systolic blood pressure is = 120 mm Hg in the general population and the distribution of systolic blood pressures is approximately normal. In the Honolulu Heart Study, a sample of n = 25 people had an average systolic blood pressure of 130 mm Hg with a standard deviation of 20mm Hg. Is the group in the study significantly different from the regular population?

What are the null and alternative hypothesis?

i.

Alt: µ>130 Null: µ=130

Alt: µ130 Null: µ=120

Alt: µ>12 Null: µ=120

Alt: µ120 Null: µ=120

What distribution should be used to conduct the test?

i.Standard Normal Distribution (Z)

ii.T Distribution

iii.F Distribution

iv. Distribution

What is the result of your test? = 0.01

i.There is enough evidence to conclude that the .

ii.There is enough evidence to conclude that the .

There is NOT enough evidence to conclude that the group in the study is significantly different from the regular population

Explanation / Answer

(i)

Alt: µ120 Null: µ=120

as population std deviation is unknown

ii.T Distribution

for above std error of mean =std deviatrion/(n)1/2 =20/(25)1/2 =4

test statistic t =(X-mean)/std error =(130-120)/4=2.5

for above test statistic and (n-1=24) degree of freedom ; p value =0.0197

as p value is greater then = 0.01

hence There is NOT enough evidence to conclude that the group in the study is significantly different from the regular population

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