(6 points total) At the end of a production run manufacturing rubber gaskets, it
ID: 2936443 • Letter: #
Question
(6 points total) At the end of a production run manufacturing rubber gaskets, items are sampled at random and inspected to determine if the item is Acceptable (A), or Defective (D). Suppose it is planned to select two items and determine if each is either A or D. a. (2 points) What is the sample space S of the outcomes? S = {AA, AD, DA, DD} b. (4 points) What is the probability that both of the selected gaskets are defective? Show all necessary work.
My question is on part b. I have the answer and the answer uses a numeric value of 0.07 for each of the probabilities of being defective.
So, P(1st D and 2nd D)= P(1st D)*P(2nd D) ---> 0.07*0.07= 0.0049
My question is where do they get 0.07 from if it is not given in the question?
Explanation / Answer
0.07 is nothing but the probability that the item is defective,
which should be mentioned in the question, but somehow it
is missing.
Since the event that an item is defective is independent of the
other item, so, the probability that both the item will be
defective = (0.07 * 0.07) = 0.0049.
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