The number of defective items produced in a week by each of 5 different producti

Question

The number of defective items produced in a week by each of 5 different production lines (called A B C D and E ) is as follows A B C D E Total 15 27 31 19 11 103 This data will be used to test if the lines are of equal quality, i.e. H0:p1=p2=p3=p4=p5=0.2H0:p1=p2=p3=p4=p5=0.2.

The p-value for this test is 0.0096. What are the appropriate decision and conclusion at the 1% significance level?

Select one or more: We reject the null hypothesis.

We cannot reject the null hypothesis.

There is evidence that the production lines are not of equal quality.

There is not enough evidence to say that the production lines are not of equal quality.

Explanation / Answer

Reject the null hypothesis if p-value is less than significance level

Do not reject reject null hypothesis if p-value is greater than significance level

Given p-value = 0.0096

Significance level = 1/100 = 0.01

0.0096 < 0.01 p-value is less than significance level ; therefore reject null hypothesis.

Null hypothesis : Ho : p1=p2=p3=p4=p5 = 2; which the test is rejecting

Concludes that there is evidence that the production lines are not equal quality

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