Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health.

Question

Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body bone mineral content (TBBMC). A highly skilled operator is required to take the measurements. Recently, a new DXA machine was purchased by a research lab, and two operators were trained to take the measurements. TBBMC for eight subjects was measured by both operators. The units are grams (g). A comparison of the means for the two operators provides a check on the training they received and allows us to determine if one of the operators is producing measurements that are consistently higher than the other. Here are the data.

(a)Take the difference between the TBBMC recorded for Operator 1 and the TBBMC for Operator 2. (Use Operator 1 minus Operator 2. Round your answers to four decimal places.)

xbar= -0.0024 s= 0.0105

Use a significance test to examine the null hypothesis that the two operators have the same mean. Give the test statistic. (Round your answer to three decimal places.)

t = ????

Give the degrees of freedom= 7

Give the P-value. (Round your answer to four decimal places.= 0.7352

Give your conclusion. (Use the significance level of 5%.)

We cannot reject H0 based on this sample.We can reject H0 based on this sample.   

The sample here is rather small, so we may not have much power to detect differences of interest. Use a 95% confidence interval to provide a range of differences that are compatible with these data. (Round your answers to four decimal places.) ???

The answers above are correct, however i am having trouble finding the test statistic. I know the p value is 0.7352. Please explain how find the test statistic and the pvaule. Thanks!

Subject Operator 1 2 3 4 5 6 7 8 1 1.328 1.335 1.075 1.226 0.939 1.005 1.179 1.286 2 1.323 1.322 1.073 1.233 0.934 1.019 1.184 1.304

Explanation / Answer

std error =s/(n)1/2 =0.0105/(8)1/2 =0.0037

here as we know that test statistic =(xbar)/std error =-0.0024/0.0037 =-0.6397

for p value please tell me which mode you are using so that I may help you,

for 95% CI; and 7 degree of freedom, value of t= 2.3646 therefore confidence interval= sample mean -/+ t*std error lower confidence limit -0.0112 upper confidence limit 0.0064

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