Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

(d) The researcher would like to provide a point estimate which describes the av

ID: 2933581 • Letter: #

Question

(d) The researcher would like to provide a point estimate which describes the averuge quality af win hich iare a pliofas, a color of 2a, and a polymeric of 1.0 and a 95% interval for this value. R syntax and out put is provided below. Report the predicted value and "confidence) upr 1 12.99814 11.60597 14.39032 1 12.99814 10.04051 15.95577 The researcher decides to fit a reduced model using only color as a predictor. Summary information for this reduced model is below. wineReduced - ia(quality color, data vineDat) Coefficients Estimate Std Error t value Pr( tl) (Intercept) 11.6709 0.7074 16.499 2e-16 color 0.8473 xXx XXx Residual standard error: 1.272 on 30 degrees of freedon Multiple R-aquared: 0.5008, Adjusted R-squared: 0.4841 F-statistic: 30.09 on 1 and 30 DF· p-value : 5.912e-06 () Which of the two models fits better? Provide brief justification for your answer. (f) Will the standard error for the color variable for the reduced model (which is not given) be larger or smaller than the standard error for color reported for the full model? Answer "Larger" or Smaller", then provide an explanation for your answer.

Explanation / Answer

d)

The predicted value is 12.99814 and the 95% prediction interval is (10.04051, 15.95577)
These are the outputs of the command with parameter interval = "prediction"

e)
The residual standard error of the reduced model (1.272) is less than the residual standard error of the full model (1.274), so the reduced model fits the data well.

f)

"Smaller" The coefficient of color variable in the reduced model is 0.8473 which is less than the coefficient of  color variable in the full model 0.9546. So, the Standard error of the color variable for the reduced model will be smaller than that of the full model.